simple question Why noise devided by two (N0/2) ? is it average value of noise +ve and -ve. gaussian channel consider zero or white?

# Noise

Started by ●March 6, 2006

Reply by ●March 6, 20062006-03-06

"Almas_Uddin_Ahmed" <almas.mmu@gmail.com> writes:> simple question > Why noise devided by two (N0/2) ? is it average value of noise +ve and > -ve.I think it's just a convenience factor due to the way we normally think about bandwidth. Normally, if we say a signal has bandwidth B Hz, what we mean is it is a) real, and b) non-zero from 0 to B Hz. When working with the "complex baseband signal," such a signal has non-zero energy from -B to +B. Thus if you have white noise PSD of N0/2, and you integrate over -B to +B, you get the nice result that the toal noise power is B*N0 watts. -- % Randy Yates % "And all that I can do %% Fuquay-Varina, NC % is say I'm sorry, %%% 919-577-9882 % that's the way it goes..." %%%% <yates@ieee.org> % Getting To The Point', *Balance of Power*, ELO http://home.earthlink.net/~yatescr