using unique() for array

using unique() for array

ansarigmbhansarigmbh Posts: 24Questions: 7Answers: 0

Hi

when I used this code:

table.column(1).data().unique(); 

The returned value was not an array that contains unique values. In this column I have an array for each cell.

[["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["1", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4"], ["4", "8"], ["1", "2", "4"], ["2", "4"], ["2", "4"], ["4", "16"], ["4", "16"], ["2", "4"], ["1", "4"], ["4", "16"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"], ["2", "4"]]

what should I do?

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Answers

  • allanallan Posts: 57,254Questions: 1Answers: 9,118 Site admin
    Answer ✓

    The unique() method will compare the objects at the top level - so in Javascript ["1", "4"] !== ["1", "4"] hence why unique doesn't work for your use case.

    If you need to check if the inner arrays are unique, you would need to perform the loop check yourself.

    Allan

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