"Check All" button with pagination

"Check All" button with pagination

wiggsflywiggsfly Posts: 3Questions: 0Answers: 0
edited March 2009 in General
I have the following "Check All" function, however it only checks the first page with paginated data. Any suggestions?

this.checkAll = function(pageSize) {
var anSelected = oTable.fnGetNodes();
$(document).ready(function(){
for (var i = 0; i < pageSize; i++) {
$(anSelected[i]).addClass('row_selected');
}
});
}

Replies

  • allanallan Posts: 61,840Questions: 1Answers: 10,134 Site admin
    Hi wiggsfly,

    Where is the "pageSize" variable coming from? What I think you can probably just in your "for" loop is:

    [code]
    for (var i = 0; i < anSelected.length; i++)
    [/code]

    The fnGetNodes() API function returns an array of all TR nodes in the table, so it's length will match what is currently available via paging.

    Allan
  • wiggsflywiggsfly Posts: 3Questions: 0Answers: 0
    Thanks allan, I've used that technique as well however that selects all the records in the entire table and what I really need to do is select all the records I can see on the given page (assuming pagination). Any suggestions?

    Thanks,
    Chris
  • allanallan Posts: 61,840Questions: 1Answers: 10,134 Site admin
    Oh I see - sorry - from your original post I thought you could get the data from the first page, but not the full data. Okay, so what you could do then is one of two things:

    1. Get the number of TR elements from the DOM and bypass DataTables for that little part. For example $('#example tbody tr').length would do).

    2. Use the settings information to figure out how many records are displayed.

    [code]
    /* DataTables 1.4 */
    var oSettings = oTable.fnSettings();
    int iDisplay = oSettings._iDisplayEnd - oSettings._iDisplayStart;

    /* DataTables 1.5 */
    var oSettings = oTable.fnSettings();
    int iDisplay = oSettings.fnDisplayEnd() - oSettings._iDisplayStart;
    [/code]

    Regards,
    Allan
  • wiggsflywiggsfly Posts: 3Questions: 0Answers: 0
    Thank you. That's exactly what I was looking for.

    Chris
  • sidsid Posts: 2Questions: 0Answers: 0
    edited December 2009
    Hi Allan,
    First of all, you have created a great plug-in.

    I have 20 rows in my table sorted by the row number 1 - 20. The table is set to display 10 rows at a time. Therefore, I have two pages to click next and previous. The first page displays 1-10 and the second page displays 11-20. My check all code works great when the table is first displayed and even when the next and previous buttons are clicked.
    Now I sort a column so that my first page is displaying rows 5 - 14. The check all code only selects the rows 5-10 instead of checking all of the displayed rows. Do you know of a work around to get this working right? I just cannot find anything in the forum and I'm a javascript newbie

    [code]
    var oSettings = myTable.fnSettings();
    var start = oSettings._iDisplayStart;
    var end = oSettings._iDisplayLength;
    var counter = oSettings.fnDisplayEnd() - oSettings._iDisplayStart;
    for ( var i = start; i < counter; i++) {
    var node = $('input[name=selectedItems]', itemsMgmtTable.fnGetNodes(i));
    node.attr('checked', element.checked);
    }
    [/code]
  • sidsid Posts: 2Questions: 0Answers: 0
    edited December 2009
    This is what I ended up doing that worked for me:
    [code]
    var oSettings = itemsMgmtTable.fnSettings();
    var start = oSettings._iDisplayStart;
    var end = parseInt(oSettings.fnDisplayEnd());

    for ( var i = start; i < end; i++) {
    var nRow = oSettings.aoData[ oSettings.aiDisplay[i] ].nTr;
    var chkNode = $('input[name=selectedItems]', nRow);
    chkNode.attr('checked', element.checked);
    }
    [/code]
  • allanallan Posts: 61,840Questions: 1Answers: 10,134 Site admin
    edited December 2009
    Hi sid,

    Good to hear you got it sorted. A possibly slightly shorter version:

    [code]
    /* For all row in the table */
    $( "input[name=selectedItems]", itemsMgmtTable.fnGetNodes() ).attr('checked', element.checked);

    /* For only visible row in the table */
    $( "input[name=selectedItems]" ).attr('checked', element.checked);
    [/code]
    Warning - I've not actually tested this code - but I think it should work fine :-)

    Regards,
    Allan
This discussion has been closed.